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C語言 文件加密解密
根據(jù)你的需要，修改了之前的代碼。
#include?stdio.h
#include?string.h
#include?stdlib.h
#include?time.h
const?unsigned?int?MAX_KEY_LENGTH?=?1000;
int?encode(char?const?*datafile,?char?const?*keyfill);
int?decode(char?const?*datafile,?char?const?*keyfile);
int?loadKey(char?const?*keyfile,?int?*keys,?unsigned?int?size);
int?saveKey(char?const?*keyfile,?int?*keys,?unsigned?int?size);
int?generateKey(int?*keys,?unsigned?int?size);
int?main(int?argc,?char?const?*argv[])
{
????char?datafile[]?=?"encrypted.txt";
????char?keyfile[]?=?"key.txt";
????int?retcode,?choice,?loop?=?1;
????char?ch[5]?=?{'\0'};
????while(1)
????{
????????printf("1.?Encryption.\n");
????????printf("2.?Decryption.\n");
????????printf("3.?Exit.\n");
????????printf("Selection?(1,2,3):");????????
????????fgets(ch,?sizeof(ch),?stdin);
????????sscanf(ch,?"%d",?choice);????????
????????switch(choice)
????????{
????????????case?1:?????????????????
????????????????retcode?=?encode(datafile,?keyfile);
????????????????if?(retcode?!=?0)?printf("error,?%d\0",?retcode);
????????????????break;
????????????????
????????????case?2:????????????????????????????????
????????????????retcode?=?decode(datafile,?keyfile);
????????????????if?(retcode?!=?0)?printf("error,?%d\0",?retcode);
????????????????break;
????????????????
????????????case?3:
????????????????loop?=?0;
????????????????break;
????????????default:
????????????????;
????????????????break;????
????????}????????
????????if?(0?==?loop)?break;
????}????
????return?0;
}
int?generateKey(int?*keys,?unsigned?int?size)?
{
????char?str[]="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz,./;\"'?";????
????size_t?str_len?=?sizeof(str)/sizeof(str[0]);
????int?i;
????
????srand(time(NULL));
????for?(i?=?0;?i??size;?++i)
????????keys[i]?=?str[rand()?%?str_len];
????return?0;
}
int?loadKey(char?const?*keyfile,?int?*keys,?unsigned?int?size)
{
????int?i?=?0;
????FILE?*pfile;????
????int?retcode?=?0;
????pfile?=?fopen(keyfile,?"r");
????if?(pfile?==?NULL)?return?-1;
????while?(?!feof(pfile)?)?{
????????if?(i??size)
????????????fscanf(pfile,?"%d?",?keys[i++]);
????????else????????
????????????break;????????
????}
????fclose(pfile);
????return?i;
}
int?saveKey(char?const?*keyfile,?int?*keys,?unsigned?int?size)?
{
????FILE?*pfile;
????int?i;
????pfile?=?fopen(keyfile,?"w");
????if?(pfile?==?NULL)?return?-1;
????
????for(i?=?0;?i??size;?++i)?{
????????fprintf(pfile,?"%d?",?keys[i]);
????}
????fclose(pfile);
????return?0;
}
int?encode(char?const?*datafile,?char?const?*keyfile)?
{
????char?original[MAX_KEY_LENGTH]?=?{'\0'};
????char?encrypted[MAX_KEY_LENGTH]?=?{'\0'};
????int?i,?size;
????int?keys[MAX_KEY_LENGTH];
????FILE?*pdatafile,?*pkeyfile;
????
????pkeyfile?=?fopen(keyfile,?"w");
????if?(NULL?==?pkeyfile)?return?-1;
????fclose(pkeyfile);????
????puts("?input?message:");
????gets(original);
????size?=?strlen(original);
????if?(0?!=?generateKey(keys,?size))?return?-2;
????if?(0?!=?saveKey(keyfile,?keys,?size)?)?return?-3;
????
????pdatafile?=?fopen(datafile,?"w");
????if?(NULL?==?pdatafile)?return?-4;
????for?(i?=?0;?i??size;?++i)?{
????????encrypted[i]?=?original[i]?+?keys[i];
????????fputc(encrypted[i],?pdatafile);
????????fputc(encrypted[i],?stdout);
????}
????printf("\n");
????fclose(pdatafile);
????return?0;
}
int?decode(char?const?*datafile,?char?const?*keyfile)
{
????FILE?*pdatafile,?*pkeyfile;
????int?keys[MAX_KEY_LENGTH]?=?{0};
????char?original[MAX_KEY_LENGTH]?=?{'\0'};
????char?encrypted[MAX_KEY_LENGTH]?=?{'\0'};
????int?i,?size;
????pkeyfile?=?fopen(keyfile,?"r");
????if?(NULL?==?pkeyfile)?return?-1;
????fclose(pkeyfile);
????pdatafile?=?fopen(datafile,?"r");
????if?(NULL?==?pdatafile)?return?-2;
????
????fscanf(pdatafile,"%s",encrypted);
????fclose(pdatafile);
????size?=?loadKey(keyfile,?keys,?MAX_KEY_LENGTH);
????if?(size??1)?return?-3;
????
????for?(i?=?0;?i??strlen(encrypted);?++i)?{
????????original[i]?=?encrypted[i]-keys[i];
????????fputc(original[i],?stdout);
????}
????printf("\n");
????return?0;
}
運(yùn)行結(jié)果：
1. Encryption.
2. Decryption.
3. Exit.
Selection (1,2,3):1
?input message:
this is A test!
╓┐?╞L?╗ù|t▄╬╢╒è
1. Encryption.
2. Decryption.
3. Exit.
Selection (1,2,3):2
this is A test!
1. Encryption.
2. Decryption.
3. Exit.
Selection (1,2,3):3
[img]如何用c語言加密和解密漢字
漢字應(yīng)該是char類型的數(shù)據(jù)。你可以用強(qiáng)制類型轉(zhuǎn)換將其轉(zhuǎn)換為ASCII碼，加密的時(shí)候加上2，然后下次解密的時(shí)候減去2，在強(qiáng)制轉(zhuǎn)換為char類型的數(shù)據(jù)。代碼大概就像這樣：
int JiaMi(char s)
{
return (int)(s + 2);
}
char JieMi(int code)
{
return (char)(code - 2);
}
C語言（文件的移位與加密解密）
這道題，并不難，只是樓主，沒有說清，是就字母移位嗎？
但是看你的例子，有不全是。
程序如下：
#include stdio.h
#include stdlib.h
FILE *source;//源文件
FILE *destination;//目標(biāo)文件
int key;//密鑰
char file[100];//文件名
void encryption()//加密
{
char ch;
printf("請輸入要加密的文件名\n");
scanf("%s",file);
if((source=fopen(file,"r"))==NULL)
{
printf("無法打開文件!\n");
exit(0);
}
printf("請輸入加密后的文件名\n");
scanf("%s",file);
if((destination=fopen(file,"w"))==NULL)
{
printf("無法創(chuàng)建文件!\n");
exit(0);
}
printf("請輸入密鑰\n");
scanf("%d",key);
ch=fgetc(source);
while(ch!=EOF)
{
if(ch=='\n')
{
fputc(ch,destination);
ch=fgetc(source);
continue;
}
ch+=key;
fputc(ch,destination);
ch=fgetc(source);
}
fclose(source);
fclose(destination);
}
void decrypt()//解密
{
char ch;
printf("請輸入要解密的文件名\n");
scanf("%s",file);
if((source=fopen(file,"r"))==NULL)
{
printf("無法打開文件!\n");
exit(0);
}
printf("請輸入加密后的文件名\n");
scanf("%s",file);
if((destination=fopen(file,"w"))==NULL)
{
printf("無法創(chuàng)建文件!\n");
exit(0);
}
printf("請輸入密鑰\n");
scanf("%d",key);
ch=fgetc(source);
while(ch!=EOF)
{
if(ch=='\n')
{
fputc(ch,destination);
ch=fgetc(source);
continue;
}
ch-=key;
fputc(ch,destination);
ch=fgetc(source);
}
fclose(source);
fclose(destination);
}
int main()//主函數(shù)提供菜單
{
int choice=0;
printf("******************\n");
printf("1 文件加密\n");
printf("2 文件解密\n");
printf("3 退出\n");
printf("******************\n");
printf("請輸入1 2 3選擇操作\n");
scanf("%d",choice);
switch(choice)
{
case 1:encryption();break;
case 2:decrypt();break;
case 3:break;
}
return 0;
}
C語言加密解密問題。
樓主你好！
你應(yīng)該是想通過異或進(jìn)行簡單的加密吧！
# includestdio.h
# includestring.h
# includestdlib.h
int main(void)
{
char key;
char str[10];
int i;
printf("請輸入密鑰：");
scanf("%c",key);
fflush(stdin);
printf("請輸入要加密的文字：\n");
scanf("%s",str);
int len=strlen(str);
for(i=0;ilen;i++)
{
str[i]=str[i]^key;
}
printf("密文:\n");
printf("%s\n",str);
printf("解密：\n");
for(i=0;ilen;i++)
{
str[i]=str[i]^key;
}
printf("%s\n",str);
system("pause");
}
以上代碼已經(jīng)改正！可以運(yùn)行！
總的說！你的代碼有兩個(gè)問題！
第一，下面這段是不是多余了??？
for(i=0;istrlen(str);i++)
{
str[i]=str[i]^key;
}
第二，就是for()里面就不應(yīng)該用strlen(str)，假如你密鑰是a，加密的密文是abc，是不是導(dǎo)致第一輪循環(huán)就使得str[0]=0；再判斷istrlen(str)就會(huì)導(dǎo)致循環(huán)不退出！
所以要單獨(dú)使用一個(gè)變量len來表示數(shù)組長度！
希望我的回答對你有幫助！
? ?廣州龍躍自動(dòng)化專業(yè)破解解密各類plc加密，全國24小時(shí)聯(lián)系手機(jī)：18520649527 【關(guān)技術(shù)】 微信：guanshiyou009如有任何問題請打手機(jī)或者添加微信，謝謝支持
